Given the velocity of sound at \( 15^\circ C \): \(v_0 = 340 \, \text{m/s}\) The absolute temperatures are: \(T_0 = 15 + 273.15 = 288.15 \, \text{K}\) \(T = 47 + 273.15 = 320.15 \, \text{K}\) We use the formula for the velocity of sound: \(v = v_0 \sqrt{\frac{T}{T_0}}\) Substituting the known values: \(v = 340 \times \sqrt{\frac{320.15}{288.15}}\) Calculating the ratio of temperatures: \(\frac{320.15}{288.15} \approx 1.111\) Taking the square root: \(\sqrt{1.111} \approx 1.054\) Finally, calculating the new velocity: \(v \approx 340 \, \text{m/s} \times 1.054 \approx 358.6 \, \text{m/s}\) The velocity of sound in air at \( 47^\circ C \) is approximately: \(v \approx 358.6 \, \text{m/s}\)