The temperature of an object is raised by 120^\circC. The resulting increase in its absolute temperature is
A
50K
B
120 K
C
200K
D
393K
Verified Correct Answer: B.
Physical Principles & Numerical Solution
Object temperature = 120ºC
So, 0ºC + 273 = K
K = 120 + 273 = 393K
Increase in temperature = 0ºC to 120ºC
⇒ 273K to 393K = ( 393 - 273) = 120K
NOTE: The change in temperature in Kelvin is equal to the change in temperature in Celsius: \DeltaT(K) = \DeltaT(^\circC)
Source: Myschool Past Questions Archive (Record #59461)