The magnitude of the force experienced by a charge of 1.6 x 10\(^{-8}\)C in a uniform electric field of intensity 5 x 10\(^5\)NC\(^{-1}\) is
A
3.2 x 10\(^{-14}\)N
B
8.0 x 10\(^{-13}\)N
C
8.0 x 10\(^{-3}\)N
D
3.1 x 10\(^{13}\) N
Verified Correct Answer: C.
Physical Principles & Numerical Solution
E = \(\frac{\text{F}}{\text{q}}\)
Force F = E x q
F = 5 x 10\(^5\) x 1.6 x 10\(^{-8}\) = 8.0 x 10\(^{-3}\)N
Source: Myschool Past Questions Archive (Record #59458)