A mass of 0.5kg is whirled in a vertical circle of radius 2m at a steady rate of 2 rev/s. Calculate the centripetal force
A
164N
B
160N
C
158N
D
172N
Verified Correct Answer: C.
Physical Principles & Numerical Solution
\omega = 2\piF = 2\pi \times 2 = 4\pirad\(^{-1}\)
Centripetal force = mr\omega\(^2\)
⇒ 0.5 \times 2 \times (4\pi)\(^2\)
⇒ 157.75N
Approximately = 158N.
Source: Myschool Past Questions Archive (Record #55827)