The volume of 0.354g of helium at 273^\circC and 114cmhg of mercury pressure is 2667cm\(^3\). Calculate the volume at STP.
A
2000.25 cm\(^3\)
B
200.025 cm\(^3\)
C
4003.27 cm\(^3\)
D
2010.25 cm\(^3\)
Verified Correct Answer: A.
Physical Principles & Numerical Solution
m = 0.354g, T\(_1\) = 273^\circC = 273 + 273 = 546K
P\(_1\) = 114cmHg, V\(_1\) = 2667cm\(^3\) at STP
T\(^2\) = 273K, P\(_2\) = 76cmHg, V\(_2\) = ?
\(\frac{P_1V_1}{T_1} = \frac{P_2V_2}{T_1}\)
= 2000.25cm\(^3\)
Source: Myschool Past Questions Archive (Record #55664)