The earth's gravitational field intensity at its surface is about
(G = 6.7 \times 10\(^{-11}\)Nm\(^2\)/kg\(^2\), mass of the earth is 6 \times 10\(^{24}\)kg, radius of the earth is 6.4 \times 10\(^6\)m, g on the earth = 9.8m/s\(^2\))
A
6.7N/kg
B
7.9N/kg
C
8.0N/kg
D
9.8N/kg
Verified Correct Answer: D.
Physical Principles & Numerical Solution
E
=
F
m
=
GMm/d\(^2\)
m
=
GM
d\(^2\)
E
=
6.7 \times 10\(^{-11}\) \times 6 \times 10\(^{24}\)
(6.4 \times 10\(^6\))\(^2\)
=
9.8N
kg
E = g = 9.8N/kg
Source: Myschool Past Questions Archive (Record #55242)