(a) The earth wire is used on electrical appliances as a safety device to prevent electric shock when short circuit occurs in such appliances. The dangerous current is then passed into thq ground through the earth wire because the eartIthas a lower resistance than the body. (b) Light from a bulb connected to a single cell dim and eventually goes off because of the defects of polarization and local action. (c) (i) \(V^2\)\(_{\text{rms}}\) + \(V_c - L_L)^2\) \(V^2\)\( _{\text{rms}}\) = \(\sqrt{V^2 + (V_c - V_L)}^2\) = \(\sqrt{30^2 + (70 - 30)^2}\) = \(\sqrt{900 + 1600}\) = 50v (ii) (\(\beta\)) = X\(_L = 2\pi fL\) = 2 \(\pi \times \frac{500}{\pi} \times 0.007\) = 7 \(\Omega\) But X\(_c = \frac{1}{2 \pi fC} = \frac{1}{2 \pi \times \frac{500}{\pi} \times 0.001}\) = L\(\Omega\) z = \(\sqrt{R^2 + (X_L - X_c)^2}\) = \(\sqrt{8^2 + (7 - 1)^2} = \sqrt{64 + 36}\) = \(\sqrt{100}\) = 10\(\Omega\) I = \(\frac{v}{z} = \frac{50}{10}\) = 5.0 A (iii) (\(\gamma\)) P = I\(^2R = 5^2 \times 8\) = 200W \(V_o = V_\text{rms} \sqrt{2} = 50\sqrt{2} = 70.7V\) But V\(_osin2 \pi ft\) = 70.7\(sin 2 \times 2 \times \pi \times \frac{500}{\pi} \times t\) = 70.7sin 1000t