A wire of length 2.00 m and radius 1.0 mm is stretched by 25.0 mm on the application of a force of \(10^3\) N. Calculate Young's modulus for the wire.
Verified Correct Answer: .
Physical Principles & Numerical Solution
Given:
L = 2m r = 1mm = 1 x \(10^{-3}\)m. e = 25mm = 25 x \(10^{-3}\)m
F = 1000N
Young modulus, E = \(\frac{F \times l}{A \times e}\)
Area, A = \pir^2 = \(3.142 x (10^{-3})^2\) = \(3.142x10^{-6}\)
E = \(\frac{1000 \times 2}{3.142 \times 10^{-6} \times 25 \times 10^{-3}}\)
E = \(2.55 x 10^{10} NM^{-2}\)
Source: Myschool Past Questions Archive (Record #52981)