A projectile is fired with a velocity of 20 ms\(^{-1}\) at an angle of 40^\circ to the horizontal. Determine the components of the velocity of the projectile at its maximum height.
Verified Correct Answer: .
Physical Principles & Numerical Solution
The components of velocity at maximum height are:
Vy = 0
Vx = UCos \(\theta\) = 20 Cos 40^\circ
=15.32ms\(^{-1}\)
Source: Myschool Past Questions Archive (Record #52946)