A converging lens of focal length 10cm forms an erect image three times the size of the real object. Calculate the distance between the image and the object.
A
6.6cm
B
11.1cm
C
13.3cm
D
20.0cm
Verified Correct Answer: C.
Physical Principles & Numerical Solution
Given, image size = 3U
object size = U
focal length = 10cm
lens to object distance = \(\frac{focal length \times object size}{image size}\)
= \(\frac{10 \times u}{3u} = 3.33\)
distance between image and object = 10 + 3.33 = 13.33cm
Source: Myschool Past Questions Archive (Record #50030)