In a series R-L-C circuit, R = 10\(\Omega\), \(X_{c}\)= 4\(\Omega\) and \(X_{L}\) = 9\(\Omega\). The impedance of the circuit is
A
4.1\(\Omega\)
B
5.0\(\Omega\)
C
10.8\(\Omega\)
D
11.2\(\Omega\)
Verified Correct Answer: D.
Physical Principles & Numerical Solution
The impedance for a RLC circuit is
\(Z = \sqrt{R^{2} + (X_{L} - X_{C})^{2}}\)
= \(\sqrt{10^{2} + (9 - 4)^{2}}\)
= \(\sqrt{125}\)
= 11.18\(\Omega\) \(\approxeq\) 11.2\(\Omega\)
Source: Myschool Past Questions Archive (Record #49874)