A football is kicked at an angle of 45^\circ to the horizontal over a defense line up with a velocity of 15\(ms^{-1}\). Calculate the magnitudeof horizontal velocity of the ball at its highest point [Neglect friction, g = 10\(ms^{-2}\)].
A
0.0\(ms^{-1}\)
B
5.6\(ms^{-1}\)
C
10.6\(ms^{-1}\)
D
15.0\(ms^{-1}\)
Verified Correct Answer: C.
Physical Principles & Numerical Solution
The horizontal component of velocity, \(V_{x}\), is unaffected by the acceleration of free fall and remains constant.
\(V_{x} = U_{x} = Ucos\theta\)
= \(15 \times cos45 = 15\times 0.7071\)
\(\approxeq 10.6ms^{-1}\)
Source: Myschool Past Questions Archive (Record #49687)