Given that S = \(3t^{2}\) + 5t - 10 is displacement of a particle in metres, calculate it initial velocity.
A
10m/s
B
2m/s
C
5m/s
D
6m/s
Verified Correct Answer: C.
Step-by-Step Mathematical Solution
The initial velocity (v) is obtained by differentiating the displacement (S) with respect to time, which gives:
v = \(\frac{dS}{dt}\) = \(\frac{d}{dt}\)(\(3t^2\) + 5t - 10) = 6t + 5
The initial velocity is the velocity of the particle at time t = 0. Substituting t = 0 into the velocity equation:
v(0) = 6(0) + 5 = 5
Therefore, the initial velocity of the particle is 5 m/s.
Source: WAEC / JAMB / NECO Classroom Archive (Record #64380)