For capacitance i n parallel, 2µF and 2µF are in parallel, their equivalence is 2µF and 2µF = 4µF The 4µF generated is now in series with the remaining 4µF. The net capacitance for series connection is \(\frac{1}{C}\) = \(\frac{1}{4}\) + \(\frac{1}{4}\) = 1 + \(\frac{1}{4}\) = \(\frac{2}{4}\) C = \(\frac{4}{2}\) = 2µF