\(^{226}_{88}Ra\) emits two alpha particles to produce polonium(po) nuclide. The correct formula for the nuclide?
A
\(^{224}_{86}po\)
B
\(^{222}_{86}po\)
C
\(^{222}_{84}po\)
D
\(^{218}_{84}po\)
Verified Correct Answer: D.
Physical Principles & Numerical Solution
No expanded working has been attached for this question yet. The verified answer is Option D.
Source: Myschool Past Questions Archive (Record #45572)