in a nuclear fission process, the mass defect was 1.2 x 10-5kg. Calculate the energy released. [speed of the light in vacuum = c = 3.0 x 108ms-1]
A
1.08 x 1011J
B
5.20 x 1011J
C
1.08 x 1012J
D
2.50 x 1013J
Verified Correct Answer: C.
Physical Principles & Numerical Solution
E - Mec2
E = 1.2 x 10-5 x (3 x 108)2
E = 1.08 x 1012J
Source: Myschool Past Questions Archive (Record #45567)