Calculate the temperature of 6 moles of an ideal gas at a pressure of 7.6 x 106Nm-2 with a volume of 10-3m3.
[R = 8.3jmol-1K-1]
A
201oC
B
126oC
C
153oC
D
185oC
Verified Correct Answer: C.
Physical Principles & Numerical Solution
T = \(\frac{PV}{nR}\) = \(\frac{7.6 x 10^6 x 10^-3}{6 x 8.3}\)
= 153oC
Source: Myschool Past Questions Archive (Record #44710)