A ship H leaves a port P and sails 30 km due south. Then it sails 60km due west. What is the bearing of H from P?
A
20o 34'
B
243o 26'
C
116o 34'
D
63o 26'
E
240o 56'
Verified Correct Answer: B.
Step-by-Step Mathematical Solution
Let the bearing of H from P be represented by x^\circ.
\(\tan \theta = \frac{30}{60} = 0.5\)
\(\theta = \tan^{-1} (0.5) = 26.565^\circ\)
\(x = 180^\circ + (90 - 26.565)\)
\(x = 180 + 63.435 = 243.435^\circ\)
= \(243^\circ 26'\)
Source: WAEC / JAMB / NECO Classroom Archive (Record #32473)