A projectile fired with initial velocity, u will attain its maximum height H when the angle of projection \theta is
A
30°
B
45°
C
60°
D
75°
E
90°
Verified Correct Answer: E.
Physical Principles & Numerical Solution
The maximum height (H) of a projectile is given by:
\(H=\frac{u^2\sin^2\theta}{2g}\)
Since (u) (initial velocity) and (g) (acceleration due to gravity) are fixed, the maximum height depends on \(\sin^2\theta\).
The largest value of \(\sin\theta\) is 1, which occurs when:
\(\theta = 90^\circ\).
Source: Myschool Past Questions Archive (Record #42972)