A body is launched from the earth’s surface, of radius R, so that it just escapes from the gravitational influence of the earth; If the gravitational constant is G and the mass of the earth is M, what is the escape velocity of the boby.
A
\(\sqrt{2GM}\) ÷ R
B
\(\frac{\sqrt{2GM}}{R}\)
C
\(\frac{\sqrt{2G}}{MR}\)
D
\(\sqrt{2GMR}\)
E
\(\frac{\sqrt{R}}{2GM}\)
Verified Correct Answer: B.
Physical Principles & Numerical Solution
No expanded working has been attached for this question yet. The verified answer is Option B.
Source: Myschool Past Questions Archive (Record #42938)