The angle of elevation of the top of a cliff 15 meters high from a landmark is 60º. How far is the landmark from the foot of the cliff? Leave your answer in surd form
A
\(15\sqrt{3}m\)
B
\(15\sqrt{2}m\)
C
\(10\sqrt{3}m\)
D
\(5\sqrt{3}m\)
Verified Correct Answer: D.
Step-by-Step Mathematical Solution
Tan 60º = \(\frac{15}{x}\)
cross multiply:
x = \(\frac{15}{\sqrt3}\) = 5\(\sqrt3\)m
Source: WAEC / JAMB / NECO Classroom Archive (Record #26709)