The general equation for a wave is given by y = Asin⁡(k(x−vt)), where A is the amplitude, k is the wave number, v is the wave speed, and x and t are the position and time, respectively. The wave number k is related to the wavelength \lambda by the equation k = \(\frac{2\pi}{\lambda}\) In the given wave equation, y=0.5sin⁡(0.4\pi(x−60t)), the wave number k is 0.4\pi. Setting k = \(\frac{2\pi}{\lambda}\) equal to 0.4\pi and solving for \lambda gives: \lambda = \(\frac{2\pi}{0.4\pi}\) = 5cm So, the wavelength of the wave is 5 cm.