The acceleration of the system show above is
Attached Figure / Diagram
A
2ms-2
B
4ms-2
C
6ms-2
D
8ms-2
Verified Correct Answer: B.
Physical Principles & Numerical Solution
M\(_2\)g - M\(_2\)a = M\(_1\)a + M\(_1\)g Sin\(\theta\)
(30 x 10) - 30a = 20a + 20 x 10 x Sin 30
300 - 30a = 20a + 100
- 30a - 20a = 100 - 300
- 50a = - 200
a = \(\frac{-200}{-50}\) = 4m/s\(^2\)
Source: Myschool Past Questions Archive (Record #41729)