The diagram above shows a velocity time graph representing the motion of a car. Find the total distance covered during the acceleration and retardation of the motion
Attached Figure / Diagram
A
75m
B
150m
C
300m
D
375m
Verified Correct Answer: A.
Physical Principles & Numerical Solution
Distance during acceleration
= area of the first triangle = \(\frac{1}{2}\) x 10 x 10 = 50m
Distance during retardation( deceleration)
= area of second triangle = \(\frac{1}{2}\) x 5 x 10 = 25m
Total Distance = 50 + 25 = 75m.
Source: Myschool Past Questions Archive (Record #41716)