The fig above shows the heights of two liquids X and Y when some air is sucked out of the apparatus through the pump P. The diameter of the table in X is twice That of the Tube In Y. What is the relative density of the liquid X with respect to liquid Y
Attached Figure / Diagram
A
1/3
B
2/3
C
3
D
6
Verified Correct Answer: C.
Physical Principles & Numerical Solution
Relative density of liquid x to liquid y = \(\frac{p_x}{p_y}\) = \(\frac{h_y}{h_x}\)
= \(\frac{22.5}{7.5}\) = 3( liquid x is thrice denser than liquid y)
Source: Myschool Past Questions Archive (Record #41706)