Find the tension T\(_1\) in the diagram above if the system is in equilibrium [G = 10ms\(^{-2}\)]
Attached Figure / Diagram
A
200/√3N
B
100/√3N
C
300/√3N
D
100N
Verified Correct Answer: B.
Physical Principles & Numerical Solution
The diagram transforms into the one above:
Tan 30º = \(\frac{\text{opp}}{\text{adja}}\) = \(\frac{T_1}{100}\)
But tan 30º = \(\frac{1}{\sqrt{3}}\)
\(\frac{1}{\sqrt{3}}\) = \(\frac{T_1}{100}\)
T\(_1\) = \(\frac{100}{\sqrt{3}}\)N
Source: Myschool Past Questions Archive (Record #41696)