Three 2-µF capacitors are arranged as seen in the circuit above . The effective capacitance between E and F is
Attached Figure / Diagram
A
0.75µF
B
1.33µF
C
3.00µF
D
6.00µF
Verified Correct Answer: B.
Physical Principles & Numerical Solution
\(C_T = \frac{2 \times (2 + 2)}{2 + (2 + 2)}\)
= \(\frac{8}{6}\)
= 1.33 \(\mu\)F
Source: Myschool Past Questions Archive (Record #41687)