Calculate the weight of the body: \(W = mg = 6 \, \text{kg} \times 10 \, \text{m/s}^2 = 60 \, \text{N}\) The limiting frictional force balances the component of weight acting down the incline: \(F = W \sin \theta\) Substituting the known values: \(30 = 60 \sin \theta\) Solving for \( \sin \theta \): \(\sin \theta = \frac{30}{60} = \frac{1}{2}\) The angle \( \theta \) corresponding to \( \sin \theta = \frac{1}{2} \) is: \(\theta = 30^\circ\) The angle of inclination \( \theta \) is \(30^\circ\).