What is the acceleration of a particle whose motion is graphically displayed in the diagram above
Attached Figure / Diagram
A
0.67ms-2
B
0.83ms-2
C
0.87ms-2
D
92ms-2
E
2.0ms-2
Verified Correct Answer: A.
Physical Principles & Numerical Solution
Take a straight line(both vertical and horizontal) to touch the straight line.
Acceleration = \(\frac{\text{change in velocity}}{\text{time}}\)
Acceleration = \(\frac{8.7 - 2}{10 - 0}\) = \(\frac{6.7}{10}\) = 0.67m/s\(^2\).
Source: Myschool Past Questions Archive (Record #41611)