A cell whose internal resistance is 0.5Ω delivers a current of 4A to an external resistor,The loss voltage of the cell is
A
1.250V
B
2.000V
C
8.000V
D
0.125V
Verified Correct Answer: B.
Physical Principles & Numerical Solution
E = V + v
where E = emf of cell.
V = terminal p.d
v = loss voltage of the cell.
But from ohm's law V=IR ; v = Iv
\( \implies \) lost voltage = V = Ir
= 4 x 0.5
= 2.0v
Source: Myschool Past Questions Archive (Record #41446)