In general, the velocity of sound in air varies directly as the square root of temperature measured in kelvin. That V \( \propto \sqrt{T} \implies V^2 \propto T.\) \(\text{Therefore} \frac{V^2_1}{T_1} = \frac{V^2_2}{T_2}\) \(\text{Thus Let } V_1\) = 4m/s T\(_1\) = 10K \(\text{Therefore } V_2 = 2V_1\) = 8m/s \(\implies \frac{4^2}{10} = \frac{8^2}{T_2}\) T\(_2 = \frac{64 \times 10}{16}\) = 40K T\(_2 = 4T_1 \) Thus, when the velocity of sound in air is doubled, its absolute temperature will be quadrupled.