If two charged plates are maintained at a potential difference of 3 kv, the work done in taking a charge of 600µc across the field is
A
0.8j
B
1.8j
C
9.0j
D
18.0j
Verified Correct Answer: B.
Physical Principles & Numerical Solution
Workdone = product of the charge Q, and the p.d V.
i.e Work done = QV
= 600 * 10-6 *2.1 * 103
=1.8j
Source: Myschool Past Questions Archive (Record #41386)