\(\frac{\sin y}{3} = \frac{\sin 120^o}{5}\) sin 120o = sin 60o 5 sin y = 3 sin 60o sin y = \(\frac{3 \sin 60^o}{5}\) \(\frac{3 \times 0.866}{5}\) = \(\frac{2.598}{5}\) y = sin-1 0.5196 = 30o 18'