A 15 \(\mu F\) capacitor is connected to a 240V, 50Hz ac. source. Calculate the reactance of the capacitance [\(\pi = 3.142\)]
A
16\(\Omega\)
B
68\(\Omega\)
C
106\(\Omega\)
D
212\(\Omega\)
Verified Correct Answer: D.
Physical Principles & Numerical Solution
\(X_c = \frac{1}{2 \pi fc}\)
= 2 x 3.142 x 50 x 15 x 10-6
= 212.179\(\Omega\)
Source: Myschool Past Questions Archive (Record #35775)