A block of wood of density 0.6 gcm\(^{-3}\), weighing 3.06N in air, floats freely in a liquid of density 0.9 gcm\(^{-3}\). Calculate volume of the portion immersed (g = 10ms\(^{-2}\))
A
510cm3
B
340cm3
C
254cm3
D
170cm3
Verified Correct Answer: B.
Physical Principles & Numerical Solution
V = \(\frac{M}{D}\)
= \(\frac{3.06}{10} \times \frac{1000}{0.9} = 340\)
Source: Myschool Past Questions Archive (Record #35525)