The focal length of the eye-piece of an astronomical telescope is f1, while the focal length of the object is f2. Fro normal adjustment, the angular magnification is given by
A
\(\frac{f_2}{f_1}\)
B
1 - \(\frac{f_2}{f_1}\)
C
\(\frac{f_2}{f_1}\) - 1
D
\(\frac{f_1}{f_2}\)
Verified Correct Answer: A.
Physical Principles & Numerical Solution
No expanded working has been attached for this question yet. The verified answer is Option A.
Source: Myschool Past Questions Archive (Record #35476)