Determine the potential difference. V across the parallel resistors
Attached Figure / Diagram
A
2.0V
B
2.3V
C
3.0V
D
0.7V
Verified Correct Answer: B.
Physical Principles & Numerical Solution
6\Omega and 4\Omega are parallel.
\(\frac{1}{R_T}\) = \(\frac{1}{R_1} + \frac{1}{R_2}\)
\(\frac{1}{R_T}\) = \(\frac{1}{6} + \frac{1}{4}\)
\(R_T\) = \(\frac{12}{5}\) = 0.97\Omega
V = IR
= 0.97 x 2.4 = 2.3V
Source: Myschool Past Questions Archive (Record #35338)