simple harmonic oscillator has a period of 0.02s and amplitude of 0.25m. Calculate the speed in ms-1 at the centre of the oscillation
A
125\(\pi\)
B
25.00\(\pi\)
C
100.00 \(\pi\)
D
400.00\(\pi\)
Verified Correct Answer: B.
Physical Principles & Numerical Solution
V = WX = \(\frac{2\pi \times 0.25}{0.02} = 25\pi\)
Source: Myschool Past Questions Archive (Record #35282)