An atom \(^{234}_{91} P\) emits a gamma radiation. The resultant nuclide is
A
\(^{230}_{90} Th\)
B
\(^{234}_{91} Pa\)
C
\(^{234}_{90} Th\)
D
\(^{234}_{89} Ac\)
Verified Correct Answer: B.
Physical Principles & Numerical Solution
No expanded working has been attached for this question yet. The verified answer is Option B.
Source: Myschool Past Questions Archive (Record #34710)