The equivalent capacitance of a 3\(\mu F\) capacitor and a 6\(\mu F\) capacitor connected in parallel is
A
2.0\(\mu F\)
B
3.0\(\mu F\)
C
4.5\(\mu F\)
D
9.0\(\mu F\)
Verified Correct Answer: D.
Physical Principles & Numerical Solution
C = C1 + C2
= 3 + 6 = 9\(\mu F\)
Source: Myschool Past Questions Archive (Record #34695)