How long will it take to heat 3kg of water from 28oC to 88oC in an electric kettle taking 6a from a 220V supply? [specific heat capacity of water = 4180 J kg-1K-1]
A
120s
B
570s
C
600s
D
836s
Verified Correct Answer: B.
Physical Principles & Numerical Solution
t = \(\frac{mc\theta}{IV} = \frac{3 \times 4189 \times 60}{6 \times 120} = 570s\)
Source: Myschool Past Questions Archive (Record #34662)