Light of energy 5.0 eV falls on a metal of work function 3.0 eV and electrons are emitted, determine the stopping potential. [electronic charge, e = 1.60 x 108ms-19]
A
1.7V
B
2.0V
C
8.0V
D
15.0V
Verified Correct Answer: B.
Physical Principles & Numerical Solution
\(V_8 \frac{hf - w_o}{e} = \frac{5.0 \times 1.60 \times 10^{-19} - 3.0 \times 1.6 \times 10^{-19}}{1.6 \times 10^{-19}} = 2.0V\)
Source: Myschool Past Questions Archive (Record #34604)