A parallel plate capacitor of capacitance 600\(\mu F\) has a potential difference of 200V between its plates. Calculate the charge on either plate of the capacitor
A
1.2C
B
3.3C
C
3330.0C
D
12.0000.0C
Verified Correct Answer: A.
Physical Principles & Numerical Solution
Q = CV
= 600 x 10-6 x 200 = 1.2C
Source: Myschool Past Questions Archive (Record #34528)