Calculate the energy stored in a 20\(\mu F\) capacitor. If the p.d between the plates is 40V
A
3.2 x 10-2J
B
1.6 x 10-2J
C
8.0 x 10-4J
D
4.0 x 10-4J
Verified Correct Answer: B.
Physical Principles & Numerical Solution
W = \(\frac{cv^2}{2} = \frac{20 \times 10^{-6} \times 40^{2}}{2}\)
= 1.6 x 10-2J
Source: Myschool Past Questions Archive (Record #34400)