An elastic string of force constant 200N m-1 is stretched through 0.8m within its elastic limit. Calculate the energy stored in the string
A
64.0J
B
80.0J
C
128.0J
D
160.0J
Verified Correct Answer: A.
Physical Principles & Numerical Solution
E = \(\frac{1}{2}Ke^2\)
= \(\frac{1}{2} \times 200(0.8)^2 = 64J\)
Source: Myschool Past Questions Archive (Record #34276)