An object weighs 60.0N in air, 48.2N in a certain liquid X, and 44.9N in water, Calculate the relative density of X
A
3.300
B
1.279
C
0.932
D
0.782
Verified Correct Answer: D.
Physical Principles & Numerical Solution
R.d = Wt in Air-Wt in Air-Wt in water
= \(\frac{60.0 - 48.2}{60.0 - 44.9}\)
= 0.782
Source: Myschool Past Questions Archive (Record #34268)