A wave has an amplitude equal to 4.0m, angular speed \(\frac{1}{3} \pi\) rads-1 and phase angle \(\frac{2}{3} \pi\) rad. The displacement y of the wave particle is given as
A
y = 4 sin \(\frac{\pi}{3}\)(t + 2)
B
y = 4 sin \(\frac{\pi}{3}\)(t + \(\frac{2}{\pi}\)
C
y = 4 sin \(\frac{\pi}{3} (2t + 1)\)
D
y = 4 sin \(\frac{\pi}{3}\) (t + 1)
Verified Correct Answer: A.
Physical Principles & Numerical Solution
y = A sin(\omegat + Φ )
A = 4cm, Φ = \(\frac{2}{3} \pi \) rad, \omega = \(\frac{1}{3}\pi\ rads^{-1}\)
substituting the given values
y = 4 sin ( \(\frac{1}{3}\pi\)t + \(\frac{2}{3} \pi \))
y = 4sin \(\frac{\pi}{3}\)( t + 2)
Source: Myschool Past Questions Archive (Record #33806)