The diagram below illustrates an a.c.source of 50V(r.m.s.), \(\frac{100}{\pi}\)Hz connected in series with an inductor of inductor of inductance L and a resistor of resistance R. The current in the circuit is 2A and the p.d across L and R are 30V and 40V respectively. Calculate the average power dissipated in the circuit
Attached Figure / Diagram
A
100W
B
80W
C
60W
D
20W
E
10W
Verified Correct Answer: B.
Physical Principles & Numerical Solution
P = I2R
= 22 x 20 = 80
Source: Myschool Past Questions Archive (Record #33691)