Find the 19th term of the A.P. \(\frac{5}{6}\), \(\frac{8}{6}\), \(\frac{11}{6}\).................
A
7\(\frac{1}{2}\)
B
9
C
9\(\frac{1}{2}\)
D
9\(\frac{5}{6}\)
E
10
Verified Correct Answer: D.
Step-by-Step Mathematical Solution
first term (a) = \(\frac{5}{6}\)
common difference = \(\frac{8}{6}\) - \(\frac{5}{6}\) → \(\frac{3}{6}\) or \(\frac{1}{2}\)
A.P formula → T\(_n\) = a + (n - 1)d
T\(_n\) = \(\frac{5}{6}\) + (19 - 1)\(\frac{1}{2}\)
T\(_n\) = \(\frac{5}{6}\) + 9
→ 9\(\frac{5}{6}\)
Source: WAEC / JAMB / NECO Classroom Archive (Record #41776)