the shortest length of the air column in a resonance tube at resonance is 0.12m and the next resonance length is 0.37m. calculate the frequency of vibration given that the speed of sound in air is 340m-1
A
1360Hz
B
694Hz
C
680Hz
D
34Hz
E
340Hz
Verified Correct Answer: C.
Physical Principles & Numerical Solution
f = \(\frac{v}{2(l_2 - l_1)} = \frac{340}{2(0.37 - 0.12)} = \frac{34}{0.5}\) = 680
Source: Myschool Past Questions Archive (Record #33645)